Question

What is the force between 2 charged object that are 0.25 m apart? The charges have a value of

4.5 x 10-4 C and 5.9 x 10-5 ||

Answer 1

3823 N

Step-by-step explanation:

The magnitude of the electric force between two charges is given by Coulomb's law:

`F=k(q_1 q_2)/(r^2)`

where:

`k=9\cdot 10^9 Nm^(-2)C^(-2)` is the Coulomb's constant

`q_1, q_2` are the two charges

r is the separation between the two charges

In this problem we have:

`q_1=4.5\cdot 10^(-4)C` is the charge on the 1st object

`q_2=5.9\cdot 10^(-5)C`is the charge on the 2nd object

r = 0.25 m is the distance between the objects

Therefore, the electric force between them is:

`F=(9\cdot 10^9)((4.5\cdot 10^(-4))(5.9\cdot 10^(-5)))/((0.25)^2)=3823 N`