Question

The gap between electrodes in a spark plug is 0.060 cm. Producing an electric spark in a gasoline-air mixture requires an electric field of 3.0 × 106 V/m. What minimum potential difference must be supplied by the ignition circuit to start a car?

Answer 1

I can confirm that is the answer

Step-by-step explanation:

I did the question

Answer 2

The minimum potential difference must be supplied by the ignition circuit to start a car is -1800 V

Step-by-step explanation:

Given data,

E= 3 ×10 ⁶ Δx=0.06/100

We have to find the minimum potential difference

E= -ΔV/Δx

ΔV=- E × Δx

ΔV =-3 ×10 ⁶ . 0.06/100

ΔV=-1800 V

The minimum potential difference must be supplied by the ignition circuit to start a car is -1800 V