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As part of a math lesson on probability, Mr. Keen rolled a standard die 30 times. He predicted the die would land on three 5 times. He actually rolled a three 8 times. What is the percent error for his prediction?

User Shameel
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2 Answers

11 votes

Final answer:

The percent error of Mr. Keen's prediction that a die would land on three 5 times out of 30 rolls, when it actually landed 8 times, can be calculated to be 60%.

Step-by-step explanation:

Mr. Keen rolled a standard die, which has six sides, predicting it would land on a three 5 times out of 30 rolls. He rolled a three 8 times. To calculate the percent error for his prediction, we must first determine the difference between the observed value and the predicted value, which is 8 - 5 = 3. After that, we divide this difference by the predicted value and multiply by 100 to get the percent error:

Percent Error = (|Observed Value - Predicted Value| / Predicted Value) x 100

Percent Error = |8 - 5| / 5 x 100

Percent Error = 3 / 5 x 100

Percent Error = 0.6 x 100

Percent Error = 60%

The percent error for Mr. Keen's prediction is 60%.

User Toaster
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2 votes

Answer:

its 37.5%

Step-by-step explanation:

User Pedro Cordeiro
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