Answer:
(x + 3)(2x + 5)
Explanation:
Given
2x² + 11x + 15
Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term
product = 2 × 15 = 30 and sum = + 11
The factors are + 6 and + 5
Use these factors to split the x- term
2x² + 6x + 5x + 15 ( factor the first/second and third/fourth terms )
= 2x(x + 3) + 5(x + 3) ← factor out (x + 3) from each term
= (x + 3)(2x + 5)