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What is the vertex of the quadratic functio f(x)=(x-6)(x+2)?

User Afenster
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1 Answer

4 votes

Answer:

The vertex would be (2, -16)

Explanation:

f(x) = x²+2x-6x-12

f(x)=x²-4x-12

f'(x)= 2x-4

2x-4=0

2x=4

x=4/2

x= 2

f(2)=(2)²-4(2)-12

f(2)=-16

=(2,-16)

User Penta
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