Answer:
4.05g of MgO
Step-by-step explanation:
Mg + O₂ → MgO
From the equation of reaction,
1 mole of Mg produces 1 mole of MgO
But 1 mole = molar mass
Molar mass of Mg = 24g/ mol
Molar mass of MgO = (24+16) = 40g/mol
From the equation of reaction,
24g of Mg reacts to produce 40g of MgO
2.43g of Mg will produce x g of MgO
X = (2.43 * 40) / 24
X = 97.2 / 24 = 4.05g of 4.05g
The theoretical yield of MgO is 4.05g