Question

the balloon is inflated outdoors on a cold day in North Dakota at a temperature of -35°C to a volume of 3.0 L. The pressure remains constant. What is the volume of the balloon indoors at a temperature of 25°C?

Answer 1

The Volume of the balloon indoors in increased by 3.8 L.

Step-by-step explanation:

As per the Charles law, at constant pressure the volume of the gas is in direct proportion with the temperature measured in Kelvin. As temperature increases, the volume expands that is increases and vice-versa.

`$(V1)/(T1) = (V2)/(T2)`

T1 = -35° C + 273 K = 238 K

T2 = 25° C + 273 K = 298 K

V1 and T1 are the Volume and the temperature of the balloon inflated outdoors.

V2 and T2 are the Volume and the temperature of the balloon inflated indoors.

V2 can be found by rearranging the above equation as,

`$V2 = (V1 T2)/(T1)\\`

`$V2 = (3 L * 298 K)/(238 K)`

= 3.8 L

So the Volume of the balloon indoors in increased by 3.8 L.

Answer 2

3.75 litres is the volume of the balloon indoors at a temperature of 25°C.

Step-by-step explanation:

Data given:

initial temperature of the gas in balloon = -35°C or 238.15 K

initial volume = 3 litres

final temperature = 25 °C or 298.15 K

final volume =?

pressure remains constant

From the data given when pressure is constant Charles' law is applied.

`(V1)/(T1)` =
`(V2)/(T2)`

Rearranging the equation to know the final volume of the gas in balloon

V2 =
`(V1T2)/(T1)`

V2 =
`(3 X 298.15)/(238.15)`

V2 = 3.75 Litres

when the temperature of a gas is increased and pressure remains constant the volume of the gas increases.