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15L tank of gas is contained at a high pressure of 8.20 •10 ^4 torr. The tank is opened and the gas expands into an empty chamber with a volume of 6• 10^4 L

User Mvr
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The question is incomplete. The complete question is:

15L tank of gas is contained at a high pressure of
8.20* 10^4 torr. The tank is opened and the gas expands into an empty chamber with a volume of
6* 10^4 L. What is the final pressure if the temperature remains constant.</p><p><strong>Answer: 20.5 torr</strong></p><p><strong>Explanation:</strong></p><p>To calculate the new pressure, we use the equation given by <strong>Boyle's law. </strong>This law states that pressure is directly proportional to the volume of the gas at constant temperature. </p><p>The equation given by this law is:</p><p>[tex]P_1V_1=P_2V_2

where,


P_1\text{ and }V_1 are initial pressure and volume.


P_2\text{ and }V_2 are final pressure and volume.

We are given:


P_1=8.20* 10^4torr\\V_1=15L\\P_2=?\\V_2=6* 10^4L

Putting values in above equation, we get:


8.20* 10^4* 15L=P_2* 6* 10^4L\\\\P_2=20.5torr

Thus new pressure will be
20.5torr

User Erlend
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