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What is the value of the charge that experiences a force of 2.4 × 10–3 n in an electric field of 6.8 × 10–5 n/c?

User Stakri
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4.4k points

2 Answers

6 votes

Answer:

3.5 x 10^1C

Step-by-step explanation:

edge 2021

User Johnm
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4.1k points
4 votes

Answer:

The value of charge is 35.3 C

Step-by-step explanation:

Given:

Force
F = 2.4 * 10^(-3) N

Electric field
E = 6.8 * 10^(-5) (N)/(C)

According coulomb's law,


F = qE

Where
q = charge that experience a force,

For finding the value of charge,


q = (F)/(E)


q = (2.4 * 10^(-3) )/(6.8 * 10^(-5) )


q = 35.3 C

Therefore, the value of charge is 35.3 C

User Tinkerbelle
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4.4k points