Answer : The volume of 3.0 M spinach solution added should be, 50 mL
Explanation :
Formula used :
![M_1V_1=M_2V_2](https://img.qammunity.org/2021/formulas/chemistry/high-school/n40bndezzxpor89paazvehqq2q8qjot9ri.png)
where,
are the initial molarity and volume of spinach solution.
are the final molarity and volume of diluted spinach solution.
We are given:
![M_1=3.0M\\V_1=?\\M_2=0.30M\\V_2=500.0mL](https://img.qammunity.org/2021/formulas/chemistry/middle-school/wrerc5yzneivx2pk4tua6nbn77rz4t1smp.png)
Now put all the given values in above equation, we get:
![3.0M* V_1=0.30M* 500.0mL\\\\V_1=50mL](https://img.qammunity.org/2021/formulas/chemistry/middle-school/nem2f8qt4lugbkfiphuz3vxzlrd1i5zo0n.png)
Hence, the volume of 3.0 M spinach solution added should be, 50 mL