Answer:
c) 0.932
99% confidence interval for average weights of all packages sold in small meat trays.
(0.932 ,1.071)
Explanation:
Explanation:-
Given random sample of 35 packages in small meat trays produced weight with an average of 1.01 lbs. and standard deviation of 0.18 lbs.
size of the sample 'n' = 35
mean of the sample x⁻= 1.01lbs
standard deviation of the sample 'S' = 0.18lbs
The 99% confidence intervals are given by
![(x^(-) - t_(\alpha ) (S)/(√(n) ) , x^(-) +t_(\alpha ) (S)/(√(n) ) )](https://img.qammunity.org/2021/formulas/mathematics/college/pcyw4yiahp5x28sobd711j6d16ueu2vsfe.png)
The degrees of freedom γ=n-1 =35-1=34
tₐ = 2.0322
99% confidence interval for average weights of all packages sold in small meat trays
![(1.01 - 2.0322 (0.18)/(√(35) ) , 1.01+2.0322 (0.18)/(√(35) ) )](https://img.qammunity.org/2021/formulas/mathematics/college/b24pbyatjcyc05xa1auoes9ffvmvo3fqfv.png)
( 1.01 - 0.06183 , 1.01+0.06183)
(0.932 ,1.071)
Final answer:-
99% confidence interval for average weights of all packages sold in small meat trays.
(0.932 ,1.071)