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A new manager of a small convenience store randomly samples 20 purchases from yesterday’s sales. The mean was $45.26 and the standard deviation was $20.67. We wish to test for evidence that the overall mean purchase amount is at least $40? What is the value of the t-statistic for this test (three decimal places)?

User Achu
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1 vote

Answer:

The value of the t-statistic for this test is 1.138.

Explanation:

We are given that a new manager of a small convenience store randomly samples 20 purchases from yesterday’s sales. The mean was $45.26 and the standard deviation was $20.67.

We wish to test for evidence that the overall mean purchase amount is at least $40

Let
\mu = overall mean purchase amount

SO, Null Hypothesis,
H_0 :
\mu
\geq $40 {means that the overall mean purchase amount is at least $40}

Alternate Hypothesis,
H_A :
\mu < $40 {means that the overall mean purchase amount is less than $40}

The test statistics that will be used here is One-sample t test statistics because we don't know about the population standard deviation;

T.S. =
\frac{\bar X -\mu}{{(s)/(√(n) ) } } ~
t_n_-_1

where,
\bar X = sample mean sale = $45.26

s = sample standard deviation = $20.67

n = sample of purchases = 20

So, test statistics =
\frac{45.26-40}{{(20.67)/(√(20) ) } } ~
t_1_9

= 1.138

Hence, the value of the t-statistic for this test is 1.138.

User Vitaliis
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