Question

Fiber optics are an important part of our modern internet. In these fibers, two different glasses are used to confine the light by total internal reflection at the critical angle for the interface between the core Core S 1517 and the cladding (ncladding 1.465) cladding Randomized Variables Core I-517 core 1.465 cladding Otheexpertta.com 50%

Part (a) Numerically, what is the largest angle (in degrees) a ray will make with respect to the interface of the fiber 0 and still experience total internal reflection?
Part (b) Suppose you wanted the largest angle at which total internal reflection occurred to be 0 5 degrees. What index of refraction does the cladding need if the core is unchanged?

Answer 1

a) the largest angle is 15.05°

b) index of refraction, h = 1.5112

Step-by-step explanation:

a)

`\theta_(critical) = Sin^(-1)((h_(clad))/(h_(core)))`

90 - θ >
`Sin^(-1)((h_(clad))/(h_(core)))`

90 - θ >
`Sin^(-1)((1.465)/(1.517))` = 74.95

90 - θ > 74.95

- θ > 74.95 - 90

θ > -74.95 + 90

θ > 15.05°

b)

90° -
`\theta_c` >
`Sin^(-1)((h_(clad))/(1.517))`

90° - 5° >
`Sin^(-1)((h)/(1.517))`

85° >
`Sin^(-1)((h)/(1.517))`

h = 1.517 × Sin 85°

h = 1.517 × 0.9962

h = 1.5112