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A pet store has 9 ​puppies, including 2 ​poodles, 4 ​terriers, and 3 retrievers. If Rebecka selects one puppy at​ random, the pet store replaces the puppy with a puppy of the same​ breed, then Aaron chooses a puppy at random. Find the probability that they both select a poodle.

2 Answers

3 votes

Final answer:

The probability that both Rebecka and Aaron select a poodle is 4/81, calculated by multiplying the individual probabilities of selecting a poodle for each person (2/9 for both Rebecka and Aaron).

Step-by-step explanation:

The question inquires about the probability of both Rebecka and Aaron selecting a poodle from a pet store that has an assortment of puppies if Rebecka's selection is replaced with another puppy of the same breed before Aaron makes his choice. We begin by calculating the probability of Rebecka picking a poodle, which is the number of poodles divided by the total number of puppies. With 2 poodles and 9 total puppies, the probability is 2/9.

Since the pet store replaces the puppy with one of the same breed, the probabilities remain unchanged for Aaron's selection. Thus, the probability of Aaron also picking a poodle remains 2/9. To find the combined probability of both events happening, we multiply the probabilities of each individual event: (2/9) × (2/9) = 4/81. This is the final probability that both Rebecka and Aaron will pick a poodle.

User Cactus Philosopher
by
5.5k points
6 votes

Answer:

128.86cm squared

Step-by-step explanation:

The area of a circle is

π

r

2

πr

2

pi, r, squared.

π

×

1

cm

×

1

cm

=

1

π

cm

2

π×1cm×1cm=1πcm

2

Finally, subtract the area of the inner circle from the area of the outer rectangle.

User Jco
by
3.9k points