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What is the molarity of a solution in which 250 grams of NaCl are dissolved in 2.9 L of water?

User Simon Mayrshofer
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1 Answer

25 votes
25 votes

Answer:

About 1.48 M.

Step-by-step explanation:

The formula for molarity is mol/L.

So firstly, you must find the amount of moles in 250 grams of NaCl.

I do this by using stoichiometry. First, I find how nany grams are in a single mole of NaCl. This is around 58.44 grams/mole. Now that I know this, I can now use a stoich table. (250 g NaCl * 1 mol NaCl / 58.44 g NaCl). I plug this into my calculator.

I get that 250 grams of NaCl is equal to about 4.28 moles.

Now I just plug into the formula!

4.28 moles/2.9 L = about 1.48

I've attached a picture of my personal notes below which shows work I have done in similar equations.

What is the molarity of a solution in which 250 grams of NaCl are dissolved in 2.9 L-example-1
User Tdelaney
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