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At what temperature will a balloon have a volume of 6.08 L if the temperature is 41.0 ℃ when its volume is 4.87 L? in kelvin

User Ram Pasala
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1 Answer

5 votes

Answer:

T₂ = 251.6 K

Step-by-step explanation:

Given data:

Initial temperature = 41°C

Initial volume = 4.87 L

Final volume = 6.08 L

Final temperature = ?

Solution:

Initial temperature = 41°C (41+273.15 = 314.15 K)

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

T₂ = V₂T₁ /V₁

T₂ = 4.87 L × 314.15 K / 6.08 L

T₂ = 1529.9 L.K / 6.08 L

T₂ = 251.6 K

User Raelynn
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