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Solar energy stored in large bodies of water, called solar ponds, is being used to generate electricity. If such a solar power plant has an efficiency of 3 percent and a net power output of 150 kW, determine the average value of the required solar energy collection rate, in Btu/h.

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Answer:

17060700 btu/h

Step-by-step explanation:

Power output from power plant = 150 kW.

This power output is at 3% efficiency, this means power available in pond is 0.30P

Now, 150 kW = 0.03P

P = 150/0.03 = 5000 kW of power in the pond.

From basic conversion,

1 kW = 3412.14 btu/h

5000 kW = 5000 x 3412.14

average value of the required solar energy collection rate equal

17060700 btu/h

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