Question

A bothersome feature of many physical measurements is the presence of a background signal (commonly called "noise"). In Part 2.2.4 of the experiment, some light that reflects off the apparatus or from neighboring stations strikes the photometer even when the direct beam is blocked. In addition, due to electronic drifts, the photometer does not generally read 0.0 mV even in a dark room. It is necessary, therefore, to subtract off this background level from the data to obtain a valid measurement. Suppose the measured background level is 5.1 mV. A signal of 20.7 mV is measured at a distance of 29 mm and 15.8 mV is measured at 32.5 mm. Correct the data for background and normalize the data to the maximum value. What is the normalized corrected value at 32.5 mm?

Answer 1

0.685

Step-by-step explanation:

the background-corrected light measurement at 29mm: 20.7mv- 5.1mv⇒15.6mv

at 32.5mm: 15.8mv- 5.1mv⇒ 10.7mv

So, Normalize the data to the maximum value probably means to set the peak value to unity and scale the remaining data by the same factors.

Therefore, the normalized corrected value at 32.5mm is ⇒ 10.7mv/15.6mv ⇒0.685