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Huuuurrry plllzzzzzz. Determine the equation of the line that passes through the given points (2,6) and (4,16)

User Ben Dale
by
6.4k points

1 Answer

9 votes

Linear Equations

Linear equations are typically organized in slope-intercept form:


y=mx+b

  • m is the slope of the line
  • b is the y-intercept (the value of y when the line passes through the y-axis)

To find linear equations in slope-intercept form:

  1. Determine the slope
  2. Plug the slope into the general form
  3. Determine the y-intercept by isolating b
  4. Plug the b back into the equation

Solving the Question

We're given:

  • The line passes through the points (2,6) and (4,16)

First, determine the slope of the line.


m=(y_2-y_1)/(x_2-x_1) where
(x_1,y_1) and
(x_2,y_2) are points that fall on the line

⇒ Plug in the given points (2,6) and (4,16):


m=(16-6)/(4-2)\\\\m=(10)/(2)\\\\m=5

⇒ Therefore, the slope of the line is 5. Plug this back into the general form:


y=5x+b

Now, determine the y-intercept.


y=5x+b

⇒ Plug in one of the given points:


6=5(2)+b\\6=10+b\\b=-4

⇒ Therefore, the y-intercept is -4. Plug this back into our original equation:


y=5x-4

Answer


y=5x-4

User Valerio Bozz
by
6.5k points
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