Question

An engineer is building a new water dam. She needs the turbine to spin at least 100,00 j of kinetic energy. If the reservoir holds 1000g of water How fast must the water flow?

Answer 1

v = 141.42 m/s

Step-by-step explanation:

Mass of the water, M = 1000g = 1 kg

Kinetic energy of the turbine, KE = 10000 J

The speed of the water, v = ?

KE = 0.5 Mv²

10000 = 0.5 * 1 * v²

v² = 10000/0.5

v² = 20000

v = √20000

v = 141.42 m/s

Answer 2

The water must flow with the velocity of 141.4m/s

Step-by-step explanation:

The kinetic energy is energy due to the motion of a body

In this Case the kinetic energy of the turbine is given as

KE=1/2mv²

Where KE= kinetic energy

m= mass of water

v= velocity of the water

Data given

KE=10000j

m=1000g------kg =1000/1000= 1kg

v=?

Substituting our data into the expression we have

10,000=1/2(1*v²)

10,000=v²/2

Solving for v we have

v²=20,000

v=√20,000

v=141.4m/s