Question

A pneumatic system is producing 100 lb/in^2 of gauge pressure. A cylinder is needed to press an adhesive label onto a product. It has been determined that 5 lb of force is optimal to complete this task. What is the required diameter of the pneumatic cylinder?

Answer 1

0.25 in

Step-by-step explanation:

We are given that

Pressure,P=
`100lb/in^2`

Force,F=5 lb

We know that

`P=(F)/(A)=(F)/(\pi(d^2)/(4))`

Where
`A=(\pi d^2)/(4)`

Substitute the values

`100=(5)/(\pi* (d^2)/(4))`

`(d^2)/(4)=(5)/(100\pi)`

`d^2=(5* 4)/(100\pi)`

`d=\sqrt{(5* 4)/(100\pi)}`

`d=0.25 in`

Hence, the diameter of pneumatic cylinder=0.25 in