Answer:
P'(1100)=0.06
(see explanation below)
Explanation:
The answer is incomplete. The profit function is missing, but another function will be used as an example (the answer will not match with the options).
The profit generated by a product is given by
.
The changing rate of sales can be mathematically expressed as the derivative of the profit function.
Then, we have to calculate the derivative in function of x:
![(dP)/(dx)=(d[4x^(0.5)])/(dx)=4(0.5)x^(0.5-1)=2x^(-0.5)=(2)/(√(x))](https://img.qammunity.org/2021/formulas/mathematics/college/6ht4t092o2rt262k01ywsbnw7tzq4rgn10.png)
We now have to evaluate this function for x=1100 to know the rate of change of the sales at this vlaue of x.
![P'(1100)=(2)/(√(1100) ) =(2)/(33.16) =0.06](https://img.qammunity.org/2021/formulas/mathematics/college/sae08jqii7f0i959aq92a5vcfub88m5ohh.png)