Question

A scientist conducted an experiment. Due to chemical reaction, the temperature of a compound rose 1/10 degree every 1/4 hour for a limited time. What was the rate , in degrees per hour that the temperature of the compound rose.

Answer 1

The rate is
`(2)/(5)` degree per hour.

Explanation:

Given : A scientist conducted an experiment. Due to chemical reaction, the temperature of a compound rose
`(1)/(10)` degree every
`(1)/(4)` hour for a limited time.

To find : What was the rate, in degrees per hour that the temperature of the compound rose ?

Solution :

In every
`(1)/(4)` hour the temperature of a compound rose
`(1)/(10)` degree

To get the rate, in degrees per hour,

In every 1 hour the temperature of a compound rose is

`r=((1)/(10))/((1)/(4))` degree

`r=(4)/(10)` degree/hr

`r=(2)/(5)` degree/hr

Therefore, the rate is
`(2)/(5)` degree per hour.