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The radius of a cylindrical construction pipes is 2ft if the pipe is 24 ft long what is its volume

2 Answers

0 votes

Answer:

96π ft^3 or 301.59 ft^3 to the nearest hundredth.

Explanation:

Volume = π r^2 L (r = radius L = length).

= π * 2^2 * 24

= 96π ft^3.

User Razan Paul
by
4.3k points
4 votes

V= (3.14)x(2²)x(24)= 301.592 ft³

User Florine
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