Answer:
a) Consumption of glucose is 1.7 μmol/min.g of tissue.
The muscle produces ATP at the rate of 54.4 μmol /min.g or 0.91 μmol /sec/g.
b) The rate of consumption is s13.9 μmol /min.g or 0.23 μmol /sec/g
c) The time required (in seconds) to completely turn over the cellular pool of ATP 5.5 secs
To do this, the cell must regulate ATP synthesis very precisely
Step-by-step explanation:
a) For the oxidation of glucose we need 6 mol of O2 per mol of glucose.
Therefore, we can say consumption of glucose is at the rate of 10/6 = 1.7 μmol/min.g of tissue.
Each glucose molecule produces 32 ATP.
Then the muscle produces ATP at the rate of = 1.7x32=54.4 μmol /min.g or 0.91 μmol /sec/g.
b) For the oxidation of triglycerides whose fatty acyl chains we need 23 mol of O2 per mol of glucose.
Therefore, we can say consumption of glucose is at the rate of 10/23=0.435 μmol/min.g of tissue.
Each glucose molecule produces 32 ATP.
Then the muscle produces ATP at the rate of = 0.435x32
=13.9 μmol /min.g or 0.23 μmol /sec/g.
c) At 5 μmol /g level, it will take 5.5s to produce ATP.
This shows that the entire pool of ATP in muscle must be regenerated for every 5.5 s.