Question

How much work does the electric field do in moving a proton from a point with a potential of +145 v to a point where it is -75 v ? express your answer in joules?

Answer 1

Step-by-step explanation:

The work done by the electric field is given by:

W = qΔV

Since the positive charge moves from higher potential to lower potential, the work done in moving the proton is:

V = -q(V₂ - V₁)

W = -1.6 * 10⁻¹⁹ (-75 - 145)

W = 3.520*10³ * 10⁻²⁰ J

W = 3.520*10⁻¹⁷ J