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How much greater would the amount of traction needed be if each car were traveling at 40mph rather than 20mph

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7 votes

Answer:

4times

Step-by-step explanation:

The right-hand side of the equation
(v^(2) )/(b) computes braking distance by applying a braking coefficient factor (b) to the square of the car's velocity.

the brake coefficient is 170 and the velocity of the car is V.

At 20mph = 20^2 divides 170 = 2.3594

At 40mph = 40^2 divides 170 = 9.4117

Hence it is 4 times greater of 20mph

User Adrian Pascu
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