Answer:
Equation for the quadratic in vertex form:

Equation in standard form:

Explanation:
Recall that there is a form for writing the general equation of a parabola in vertex form:

so in our case, considering the the coordinates of the vertex (1,2) are given, we have:

Now, we can find the parameter "a" missing for the general equation, by using the information on a point (3,10) through which the parabola passes:
![y-2=a\,(x-1)^2\\(10)-2=a],(3-1)^2\\8=a\, (2)^2\\8=4\,a\\a=2](https://img.qammunity.org/2021/formulas/mathematics/high-school/6o9zpl9f72f455amti2q78woujzrq1edwl.png)
So now we have the general form of this quadratic:

which solving for "y" in order to give its standard form results in:
