answer:4.90 mol L
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1
Explanation:
Start by calculating the number of moles of glucose present in
25.5 mL
of solution.
To do that, use the molar mass of glucose
22.5
g
⋅
1 mole glucose
180.156
g
=
0.1249 moles glucose
Now, in order to find the molarity of the solution, you need to determine the number of moles of solute present in
1 L
=
10
3
mL
of solution.
The fact that you're dealing with a solution, which, as you know, is a heterogeneous mixture, i.e. it has the same composition throughout, you can use the known composition as a conversion factor to find the number of moles of solute present in
10
3
mL
of solution.
mL solution
⋅
0.1249 moles glucose
25.5
mL solution
=
4.898 moles glucose
You can thus say that the molarity of the solution is equal to
molarity = 4.90 mol L
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1
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