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In a region of space, a magnetic field points in the +x-direction (toward the right). Its magnitude varies with position according to the formula Bx=B0+bx, where B0 and b are positive constants, for x≥0. A flat coil of area A moves with uniform speed v from right to left with the plane of its area always perpendicular to this field. Part A What is the emf induced in this coil while it is to the right of the origin?

User Pepeluis
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1 Answer

5 votes

Answer:


E=Abv

Step-by-step explanation:

We are given that


B_x=B_0+bx

For
x\geq 0

Area of coil=A

Speed=v

We have to find the emf induced in the coil while it is to the right of the origin.

We know that induced emf


E=-(d\phi)/(dt)


\phi=BA


E=-(d(A(B_0+bx))/(dt)


E=-A(b)(dx)/(dt)

We know that


v=-(dx)/(dt)

Substitute the value


E=Abv

User Roomtek
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