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(3rd time Asking) Please help me with these questions!!!

(3rd time Asking) Please help me with these questions!!!-example-1

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(a) Water balloon 1 has height at time
t


h_1(t)=-16t^2-20t+110

and water balloon 2 has height


h_2(t)=-16t^2+75

Both water balloons are moving straight downward, so their distance is equal to


|h_1(t)-h_2(t)|=|(-16t^2-20t+110)-(-16t^2+65)|=|35-20t|

(b) When both water balloons are at the same height, we have
h_1(t)=h_2(t). So you could set both quadratic expressions equal to each other and solve for
t. Or you can use the fact that, when they're at the same height, the distance between them is 0. So using the expression from part (a), we have


|35-20t|=0\implies 35-20t=0\implies 35=20t\implies t=(35)/(20)

or 1.75 seconds after being thrown/dropped.

At this time, they are both at a height of
h_1(1.75)=h_2(1.75):


h_2(1.75)=-16(2.25)^2+75=26

feet.

(c) The second and fourth statements are true.

User Bezalel
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