Question

I need help but not urgent but urgent!!

Answer 1

8.6 miles (nearest tenth)

Step-by-step explanation:

`d=1.2116√(h)`

where:

• d = approximate distance a person can see (in miles)
• h = person's height above the ocean (in feet)

Captain

Given the Captain is 15 ft above the ocean:

`\implies h = 15`

Substituting this into the equation:

`\implies d_1=1.2116√(15)`

Lookout

Given the lookout is 120ft above the ocean:

`\implies h = 120`

Substituting this into the equation:

`\implies d_2=1.2116√(120)`

Solution

To find how much farther the lookout can see than the captain, subtract the distance the captain can see from the distance the lookout can see:

`\implies d_2-d_1`

`\implies 1.2116√(120)-1.2116√(15)`

`\implies 1.2116(√(120)-√(15))`

`\implies 8.579906391...`

`\implies 8.6\: \sf miles\:(nearest\:tenth)`

Answer 2

8.6 mile

Step-by-step explanation:

`\sf equation \ follows : \ \ \ d = 1.2116√(h)`

• d represents the distance a person can see.

• h represents the height above the ocean.

what the captain sees:

`\hookrightarrow \sf d_c = 1.2116√(15)`

what the sailor sees:

`\hookrightarrow \sf d_s = 1.2116√(120)`

Difference between them:

`\sf \rightarrow 1.2116√(120) \ - \ 1.2116√(15)`

`\sf \rightarrow 8.58`

`\sf \rightarrow 8.6` (rounded to nearest tenth)