Question

At Valence community college, a student can’t take more than 3 coursesunder the constraint of having no more than 7 credit hours. The purpose ofthis assignment is to construct a fee invoice for a student. This requiresthe input of Student’s id as integer and the course numbers.It costs 120.25 dollars per credit hour in addition to $35.00 charged forhealth and id services. In this project, functions must be used (noredundant code is allowed this time)Add functions as you see fit. Bottom line: Have the cleanest(minimum lines of code possible) program.

Answer 1

//C program

#include<stdio.h>

#include<string.h>

struct data{

int CRN;

char Prefix[10];

int hour;

};

void printInvoice(int id){

float price=0;

printf("\t\tVELENCE COMMUNITY COLLEGE\\\t\t\tORLANDO FL 10101\\");

printf("\t\t---------------------------\\\\");

printf("\t\t Fee invoice prepared for student V%d\\\\",id);

printf("\t\t 1 credit Hour =$120.25\\\\");

printf("\t\tCRN\tCR_PREFIX\tCR_HOURS\\");

printf("\\\t\t\t Health & id fees $ 35.00\\\\");

printf("\t\t------------------------------\\");

printf("\t\t\t Total payments\t$ %.2f\\\\",price+35);

}

int main(){

struct data d[12];

d[0].CRN=4587;

strcpy(d[0].Prefix ,"MAT 236");

d[0].hour = 4;

d[1].CRN=4599;

strcpy(d[1].Prefix,"COP 220");

d[1].hour = 3;

d[2].CRN=8997;

strcpy(d[2].Prefix,"GOL 124");

d[2].hour = 1;

d[3].CRN=9696;

strcpy(d[3].Prefix,"COP 100");

d[3].hour = 5;

d[4].CRN=4580;

strcpy(d[4].Prefix,"MAT 230");

d[4].hour = 3;

d[5].CRN=4581;

strcpy(d[5].Prefix,"MAT 231");

d[5].hour = 4;

d[6].CRN=4582;

strcpy(d[6].Prefix,"MAT 232");

d[6].hour = 2;

d[7].CRN=4583;

strcpy(d[7].Prefix,"MAT 233");

d[7].hour = 2;

d[8].CRN=3587;

strcpy(d[8].Prefix,"MAT 256");

d[8].hour = 4;

d[9].CRN=4519;

strcpy(d[9].Prefix,"COP 420");

d[9].hour = 3;

d[10].CRN=6997;

strcpy(d[10].Prefix,"GOL 127");

d[10].hour = 1;

d[11].CRN=9494;

strcpy(d[11].Prefix,"COP 101");

d[11].hour = 3;

char choice;

int id,num,i,j,not_found;

while(1){ not_found=0;

printf("Enter student id\\");

scanf("%d",&id);

printf("Enter how many courses upto 3\\");

scanf("%d",&num);

if(num>3||num<=0){

printf("Invalid number of course\\");

printInvoice(id);

}

else{

printf("Enter the %d course numbers \\",num);

int course[num];

for(i=0;i<num;i++){

scanf("%d",&course[i]);

}

int total_hour=0;

for(i=0;i<num;i++){

for(j=0;j<12;j++){

if(d[j].CRN==course[i]){

total_hour+=d[j].hour;

break;

}

}

if(j==12){

not_found=1;

break;

}

}

if(not_found){

printf("invalid crn(s)\\\\");

}

else{

if(total_hour>7){

printf("Sorry,we cannot process more than seven hour\\\\");

}

else{

float price=0;

printf("\t\tVELENCE COMMUNITY COLLEGE\\\t\t\tORLANDO FL 10101\\");

printf("\t\t---------------------------\\\\");

printf("\t\t Fee invoice prepared for student V%d\\\\",id);

printf("\t\t 1 credit Hour =$120.25\\\\");

printf("\t\tCRN\tCR_PREFIX CR_HOURS\\");

for(i=0;i<num;i++){

printf("\t\t%d\t",course[i]);

for(j=0;j<12;j++){

if(course[i]==d[j].CRN){

printf("%s\t\t%d\t$ %f\\",d[j].Prefix,d[j].hour,d[j].hour*120.25);

price+=d[j].hour*120.25;

break;

}

}

}

printf("\\\t\t\t\t Health & id fees $ 35.00\\\\");

printf("\t\t--------------------------------------------------------\\");

printf("\t\t\t Total payments\t\t$ %.2f\\\\",price+35);

}

}

}

printf("Would you like to print another invoice ? Y=yes N=no\\\\");

scanf(" %c",&choice);

if(choice=='Y')continue;

if(choice=='N')break;

printf("Invalid choice\\");

break;

}

printf("\\goodbye!");

return 0;

}

Step-by-step explanation: