Answer:
The height of the building is 400√3
Explanation:
Given:
Angle of elevation to the top of the building = 60°
Distance from the observer to the base of it = 400 ft
We have to find the height of the building.
Let the height of the building be "h" ft
Using trigonometric ratio:
⇒

So,
Considering adjacent side as 400 ft.
⇒

⇒

⇒
⇒
...tan(60) = √3
⇒
ft
The height of the building is 400 Sq-rt (3) ft in terms of radical form and in decimals it is 692.8 ft.