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The area of a circular base of the larger cylinder is 81π. The area of a circular base of the smaller cylinder is 9π.

Make a conjecture about the similar solids. How is the scale factor and the ratio of the surface areas related? Check all that apply.

- The dimensions of the larger cylinder are 3 times the dimensions of the smaller cylinder.
- The surface area of the larger cylinder is 32, or 9, times the surface area of the smaller cylinder.
- If proportional dimensional changes are made to a solid figure, then the surface area will change by the square of the scale factor of similar solids.

User NehaM
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2 Answers

7 votes

Answer:

A: The dimensions of the larger cylinder are 3 times the dimensions of the smaller cylinder.

C: If proportional dimensional changes are made to a solid figure, then the surface area will change by the square of the scale factor of similar solids

Explanation:

On edg

User EthanB
by
6.6k points
2 votes

Answer: A & C

The dimensions of the larger cylinder are 3 times the dimensions of the smaller cylinder.

If proportional dimensional changes are made to a solid figure, then the surface area will change by the square of the scale factor of similar solids.

Explanation:

User Justelouise
by
7.1k points
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