Question

Calculate the moles of calcium chloride (CaCl2) needed to react in order to produce 85.00 grams of calcium carbonate (CaCO3). use the balanced equation!

Answer 1

We need 94.3 grams of CaCl2

Step-by-step explanation:

Step 1: Data given

Mass of Calciumcarbonate ( CaCO3) = 85.00 gram

Molar mass CaCO3 = 100.09 g/mol

Molar mass of CaCl2 = 110.98 g/mol

Step 2: The balanced equation

CaCl2 + CO2 + H2O → CaCO3 + 2HCl

Step 3: Calculate moles CaCO3 produced

Moles CaCO3 = mass CaCO3 / molar mass CaCO3

Moles CaCO3 = 85.00 grams / 100.09 g/mol

Moles CaCO3 = 0.850 moles

Step 4: Calculate moles CaCl2

For 1 mol CaCl2 we need 1 mol CO2 and 1 mol H2O to produce 1 mol CaCO3 and 2 moles HCl

For 0.850 moles CaCO3 we need 0.850 moles CaCl2

Step 5: Calculate mass CaCl2

Mass CaCl2 = moles CaCl2 * molar mass CaCl2

Mass CaCl2 = 0.850 moles * 110.98 g/mol

Mass CaCl2 = 94.3 grams

We need 94.3 grams of CaCl2

Answer 2

0.85 mole

Step-by-step explanation:

Step 1:

The balanced equation for the reaction of CaCl2 to produce CaCO3. This is illustrated below:

When CaCl2 react with Na2CO3, CaCO3 is produced according to the balanced equation:

CaCl2 + Na2CO3 -> CaCO3 + 2NaCl

Step 2:

Conversion of 85g of CaCO3 to mole. This is illustrated below:

Molar Mass of CaCO3 = 40 + 12 + (16x3) = 40 + 12 + 48 = 100g/mol

Mass of CaCO3 = 85g

Moles of CaCO3 =?

Number of mole = Mass /Molar Mass

Mole of CaCO3 = 85/100

Mole of caco= 0.85 mole

Step 3:

Determination of the number of mole of CaCl2 needed to produce 85g (i.e 0. 85 mole) of CaCO3.

This is illustrated below :

From the balanced equation above,

1 mole of CaCl2 reacted to produced 1 mole of CaCO3.

Therefore, 0.85 mole of CaCl2 will also react to produce 0.85 mole of CaCO3.

From the calculations made above, 0.85 mole of CaCl2 is needed to produce 85g of CaCO3