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Find the volume of a cone with base area 9π ft2 and a height equal to twice the radius.

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2 Answers

3 votes

Answer:

18π ft³

Explanation:

Base area = pi × r² = 9pi

r² = 9

r = 3

h = 3 × 2 = 6

Volume = ⅓ × pi × r² × h

⅓ × 9pi × 6

18pi ft³

User Frederick Mfinanga
by
6.7k points
5 votes

Answer:


18\pi ft cubed

Explanation:

The volume of a cone is:
V=(1)/(3) \pi r^2h , where
\pi r^2 is the base and h is the height.

In this case, we see that the base is:
\pi r^2=9\pi. Solving for r, we see that the radius is
√(9) =3.

The height is twice the radius, so h = 2 * 3 = 6. Now, we have all the necessary values that we can plug into the equation to get the volume:


V=(1)/(3) *9\pi *6=18\pi

Thus, the answer is
18\pi ft cubed.

Hope this helps!

User SShehab
by
5.5k points
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