Question

Carlos is making phosphorus trichloride using the equation below. He uses 15.5 g of phosphorus and collects 50.9 g of phosphorus chloride.

2P +3Cl2 → 2PCl3


How much chlorine reacted with the phosphorus?

Answer 1

its c

Step-by-step explanation:

more uncomfusd

Answer 2

Answer : The mass of chlorine reacted with the phosphorus is, 53.25 grams.

Explanation :

First we have to calculate the moles of phosphorus.

`\text{Moles of phosphorus}=\frac{\text{Mass of phosphorus}}{\text{Molar mass of phosphorus}}`

`\text{Moles of phosphorus}=(15.5g)/(31g/mol)=0.5mol`

Now we have to calculate the moles of
`Cl_2`

The balanced chemical reaction is:

`2P+3Cl_2\rightarrow 2PCl_3`

From the balanced chemical reaction, we conclude that

As, 2 moles of phosphorous react with 3 moles of
`Cl_2`

So, 0.5 moles of phosphorous react with
`(3)/(2)* 0.5=0.75` moles of
`Cl_2`

Now we have to calculate the mass of
`Cl_2`

`\text{Mass of }Cl_2=\text{Moles of }Cl_2* \text{Molar mass of }Cl_2`

Molar mass of
`Cl_2` = 71 g/mol

`\text{Mass of }Cl_2=0.75mol* 71g/mol=53.25g`

Therefore, the mass of chlorine reacted with the phosphorus is, 53.25 grams.