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Rationalise 1/√7-√3
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\frac 1{\sqrt 7- \sqrt 3}\\\\\\=(\sqrt 7 + \sqrt 3)/(\left ( \sqrt 7 -\sqrt 3\right) \left( \sqrt 7 + \sqrt 3\right))\\\\\\=(\sqrt 7 + \sqrt 3)/(\left(\sqrt 7 \right)^2 - \left(\sqrt 3 \right)^2)\\ \\\\=(\sqrt 7 + \sqrt 3)/(7-3)\\\\\\=\frac 14\left(\sqrt 7 + \sqrt 3\right)

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