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What is the pH of a solution that has a [H+] of 2.5x10-OM.

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Answer:


ph \: of \: a \: solution \: = - \: log \: ( {h}^( + ) ) \\ given \: ( {h}^( + ) ) = 2 * {10}^( - 5) \\ = ph = - log \: (2 * {10}^( - 5) ) \: = 5 - log \: 2 = 4.7

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