Question

Calculate the magnitude of the magnetic force exerted on a wire that is 20 mmmm long and carries a current of 4.0 AA when it is suspended inside a solenoid at an angle of 45∘∘ to the magnetic field. The solenoid has 800 turns per meter of length and carries a current of 2.0 AA .

Answer 1

`1.14* 10^(-4)N`

Step-by-step explanation:

We are given that

Length of wire,L=20 mm=
`20* 10^(-3) m`

`1mm=10^(-3) m`

Current,I=4 A

`\theta=45^(\circ)`

Number of turns per unit length,n=800

Current,i=2 A

Magnetic field of solenoid,B=
`\mu_0ni=4\pi* 10^(-7)* 800* 2=2.01* 10^(-3) T`

Where
`\mu_0=4\pi* 10^(-7)`

Magnetic force,F=
`IBLsin\theta`

Using the formula

`F=4* 2.01* 10^(-3)* 20* 10^(-3)sin45`

`F=1.14* 10^(-4)N`