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A fixed amount of gas at 25.0 °C occupies a volume of 10.0 L when the pressure is 629 torr. Using Charles's law to calculate the volume (L) the gas will occupy when the temperature is increased 121 °C while maintaining the pressure at 629 torr.

User Hexicle
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Answer: 13.2 L

Step-by-step explanation:

To calculate the final volume of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,


(V_1)/(T_1)=(V_2)/(T_2)

where,


V_1\text{ and }T_1 are the initial volume and temperature of the gas.


V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:


V_1=10.0L\\T_1=25^oC=(25+273)K=298K\\V_2=?\\T_2=121^0C=(121+273)K=394K

Putting values in above equation, we get:


(10.0)/(298)=(V_2)/(394)\\\\V_2=13.2L

Thus the volume the gas will occupy when the temperature is increased 121 °C while maintaining the pressure at 629 torr is 13.2 L

User Smichak
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