Answer:
60.45 m
Explanation:
The ball was kicked at 39° from the edge of the building with a velocity of 17 m/s
horizontal component of the bail's velocity vₓ₀ = v₀ cos 39° = 17 m/s cos 39° = 13.211 m/s
vertical component of the ball's velocity vy₀ = v₀ sin 39° = 10.7 m/s
horizontal distance traveled ( range ) = vₓ₀ × t
63 m = 13.211 m/s t
t = 63 m / 13.211 m/s = 4.77 s
vertical distance covered
final distance - initial distance = vy₀t -
gt²
initial distance =
gt² -vy₀t = 111.49 m - ( 10.7 × 4.77) = 60.45 m