Question

A survey of 106 households was done to investigate the type of pets in the house. The results are shown in the Venn diagram below. If a household was selected at random, which of the following would be the probability the house would have cats given they don't have dogs? *

35 cats, 24 dogs, 19 both, 28 is the number outside the diagram

Answer 1

C) There should be 17,225 cat owners in town.

Explanation:

106/800 = x/130,000

Cross multiply

800x = 106(130,000)

800x = 13,780,000

Divide both sides by 800

x = 17,225

Answer 2

5/9

Explanation:

35 households have only cats, 24 have only dogs, 19 have both cats and dogs, and 28 have neither.

The total number of households without dogs is 35 + 28 = 63.

The number of these households that have cats is 35.

So the probability is 35/63 = 5/9.