99.8k views
0 votes
The half-life for the process 238u→206pb is 4.5×109 yr. a mineral sample contains 61.0 mg of 238u and 15.5 mg of 206pb. part a what is the age of the mineral

1 Answer

2 votes

Final answer:

The age of the mineral containing 61.0 mg of U-238 and 15.5 mg of Pb-206 is approximately 1.53 billion years, calculated using the half-life of U-238 and radioactive dating techniques.

Step-by-step explanation:

The age of the mineral can be determined by utilizing radioactive dating techniques based on the knowledge of the half-life of U-238, which decays into Pb-206. Given the half-life of U-238 is 4.5 × 10⁹ years, and the current amounts of U-238 and Pb-206 in the sample are 61.0 mg and 15.5 mg respectively, the age can be calculated as follows:

Let N0 be the original amount of U-238, and N be the present amount of U-238.

The formula for the number of half-lives (n) that have passed is: n = (log(N/N0))/log(1/2)

Since Pb-206 is the decay product of U-238, and assuming that all Pb-206 in the sample is from decay, N0 = N + Pb-206 amount.

Substituting the values: N0 = 61.0 mg + 15.5 mg

N0 = 76.5 mg

Using the formula: n = log(61.0 / 76.5) / log(1/2)

n ≈ 0.34

Therefore, the approximate age of the mineral is: Age = n × half-life of U-238

Age ≈ 0.34 × 4.5 × 10⁹ years

Age ≈ 1.53 × 10⁹ years

The age of the mineral is approximately 1.53 billion years.

User Vsoler
by
5.7k points