Question

a gas has a pressure of 0.410 atm and a volume of 32L. At what pressure would the volume of the gas change to 28L?

Answer 1

The new pressure is 0,469 atm

Step-by-step explanation:

We apply Boyle Mariotte's Law: for a given mass of gas at constant temperature, its pressure and volume vary inversely proportionally (the higher the pressure, the lower the volume and vice versa):

P1 x V1 = P2 xV2 We solve P2:

P2 = (P1 x V1)/V2

P2= (0,410 atm x 32 L) / 28 L

P2= 0,469 atm