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2 votes
Farmer bob was counting his cows and chickens and saw that there was 54 legs all together if he had 20 cows and chickens how many of each did he have?

User Bermo
by
5.1k points

1 Answer

4 votes

Answer: <3

7 cows and 13 chickens

Explanation:

System of Equations:

x = cows

y = chickens

x + y =20 --> y = -x + 20

4x + 2y = 54

substitute:

4x + 2(-x + 20) = 54

4x - 2x + 40 = 54

2x = 14

x = 7 cows

Now we plug in x to get y.

7 + y = 20

y = 13 chickens

User Schoob
by
5.2k points
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