Answer:
Total number of birds = 1024+512+64= 1600
A. Frequency of GG birds = 1024/1600 = 0.64
B. Frequency of Gg birds = 512/1600 = 0.32
C. Frequency of gg birds = 64/1600 = 0.04
D. According to Hardy Weinberg equilibrium
G²+2Gg+g² = 1 or G+g = 1
G² = 0.64
G= √0.64 =0.8
g² = 0.04
g= √0.04 = 0.2
A chi square test will help to know if the population is in Hardy Weinberg equilibrium.
Expected Observed Expected Deviation d² d²/E
ratio value (O) value (E) , d= O-E
0.8 1092 960 +132 17424 18.15
0.2 108 240 -132 17424 72.6
Chi square, X² =
= 90.75
Degree of freedom = n- 1= 2 - 1 = 1
P value < 0.00001. So it's significant at C value of 0.05.
Therefore, this population doesn't obey Hardy Weinberg equilibrium.