Answer:
The missing compound is H2O
Step-by-step explanation:
Step 1: Data given
H3C6H507(aq) + 3NaHCO3(aq) → Na3C6H5O7(aq) + 3C02(g) + 3
The reactants are : H3C6H507(aq) + 3NaHCO3(aq)
The products are: Na3C6H5O7(aq) + 3C02(g) and ....
Step 2:
The reactants have 11 H atoms (8 in H3C6H5O7(aq) and 3 in NaHCO3(aq))
The products have 5H atoms (in Na3C6H5O7(aq))
Here we miss 6 H atoms
The reactants have 3 Na atoms (in 3NaHCO3(aq))
The products have 3 Na atoms (in Na3C6H5O7(aq))
The amount of Na atoms on both sides is balanced. This means the missing compound is not NaOH
The reactants have 16 O atoms (7 in H3C6H507(aq) and 9 in 3NaHCO3(aq))
The products have 13 O atoms (7 in Na3C6H5O7(aq) and 6 in 3C02(g))
Here we miss 3 O atoms
The reactants have 9 C atoms (6 in H3C6H507(aq) and 3 in 3NaHCO3(aq))
The products have 9 C atoms (6 in Na3C6H5O7(aq) and 3 in 3CO2(g))
The amount of C is balanced on both sides.
This means the missing compound will not have a C atom.
Option 1 (COH2) and option 4 (COOH) are not possible
The missing compound is H2O