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For a bronze alloy, the stress at which plastic deformation begins is 277 MPa and the modulus of elasticity is 107 GPa. (a) What is the maximum load that can be applied to a specimen having a cross-sectional area of 347 mm2 without plastic deformation

User Bero
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1 Answer

6 votes

Answer:

F = 96,119 N

Step-by-step explanation:

Given that:

For a bronze alloy;

stress at which plastic deformation begins σ = 277 MPa

Modulus of elasticity = 107 GPa

Cross sectional Area = 347 mm² without plastic deformation

Considering equation relating to stress & cross sectional area

σ = F/A

The maximum load F = σA

F = 277 × 10⁶ × 347 × 10⁻⁶

F = 96,119 N

Thus, the maximum load that can be applied to a specimen having a cross-sectional area of 347 mm2 without plastic deformation = 96,119 N

User Gaurav Vashisth
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