Answer:
F = 96,119 N
Step-by-step explanation:
Given that:
For a bronze alloy;
stress at which plastic deformation begins σ = 277 MPa
Modulus of elasticity = 107 GPa
Cross sectional Area = 347 mm² without plastic deformation
Considering equation relating to stress & cross sectional area
σ = F/A
The maximum load F = σA
F = 277 × 10⁶ × 347 × 10⁻⁶
F = 96,119 N
Thus, the maximum load that can be applied to a specimen having a cross-sectional area of 347 mm2 without plastic deformation = 96,119 N